Hi,

I want to read the content of a hidden folder like

$path = '/home/user/.gnome2/folder/folder';

in a list but with

opendir(DIR, "$path") || die "folder not found" $!;

I got an error message.

Thanks for the help!
guba


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On 11-05-08 09:29 AM, guba [at] vi-anec.de wrote:
> opendir(DIR, "$path") || die "folder not found" $!;

If you are checking if the folder exists, use the -d file test:

if( -d $path ){
print "The folder $path exists\n";
}else{
print "Sorry, not path to $path\n";
}


See `perldoc perlfunc` and search for /-X/.


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>>>>> "SHC" == Shawn H Corey <shawnhcorey [at] ncf.ca> writes:

SHC> On 11-05-08 09:29 AM, guba [at] vi-anec.de wrote:
>> opendir(DIR, "$path") || die "folder not found" $!;

SHC> If you are checking if the folder exists, use the -d file test:

SHC> if( -d $path ){
SHC> print "The folder $path exists\n";
SHC> }else{
SHC> print "Sorry, not path to $path\n";
SHC> }

that doesn't tell use any more than his call to opendir failing did. we
know it isn't a legal dir from his code so he needs to see why which is
what $! tells him. he didn't tell us what $! says which i asked him to
do.

uri

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On May 8, 6:29=A0am, g... [at] vi-anec.de ("g... [at] vi-anec.de") wrote:
> Hi,
>
> I want to read the content of a hidden folder like
>
> $path =3D '/home/user/.gnome2/folder/folder';
>
> in a list but with
>
> opendir(DIR, "$path") || die "folder not found" $!;
> ... ^^^

There's a syntax error above so you would've seen an
error like this:

Scalar found where operator expected ...
near "'folder not found' $!"
(Missing operator before $!?)
syntax error at ..., near "'folder not found' $!"

'die' takes a list so you'll need a comma between
arguments or maybe just: die "folder not found: $!";

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Charles DeRykus


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