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What change is needed to this query so if =
=E2=80=9Ccurrently_in_rss=E2=80=9D is NULL it will be assigned a value =
of 0

SELECT `reference`, COUNT(`reference`) AS currently_in_rss FROM =
`ministry_profiles` WHERE `rss_feed_include` =3D 1 GROUP BY =
`rss_feed_include`

Ron

The Verse of the Day
=E2=80=9CEncouragement from God=E2=80=99s Word=E2=80=9D
http://www.TheVerseOfTheDay.info

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On Tue, Dec 14, 2010 at 4:53 PM, Ron Piggott
<ron.piggott [at] actsministries.org> wrote:
>
> What change is needed to this query so if =93currently_in_rss=94 is NULL =
it will be assigned a value of 0
>
> SELECT `reference`, COUNT(`reference`) AS currently_in_rss FROM `ministry=
_profiles` WHERE `rss_feed_include` =3D 1 GROUP BY `rss_feed_include`
>
> Ron
>
> The Verse of the Day
> =93Encouragement from God=92s Word=94
> http://www.TheVerseOfTheDay.info
>

SELECT `reference`, ifnull(COUNT(`reference`),0) AS currently_in_rss
FROM `ministry_profiles` WHERE `rss_feed_include` =3D 1 GROUP BY
`rss_feed_include`

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On 14 December 2010 21:53, Ron Piggott <ron.piggott [at] actsministries.org> wro=
te:
>
> What change is needed to this query so if =E2=80=9Ccurrently_in_rss=E2=80=
=9D is NULL it will be assigned a value of 0
>
> SELECT `reference`, COUNT(`reference`) AS currently_in_rss FROM `ministry=
_profiles` WHERE `rss_feed_include` =3D 1 GROUP BY `rss_feed_include`
>
> Ron

Doesn't that query give you an error saying that `reference` isn't in
the GROUP BY clause? I use MS SQL, so the wording my be different but
it would be along the lines of ...

For the SQL statement : SELECT POH_Contract, COUNT(POH_Contract) FROM
[BV-CLUSTER-SQL].Contracts.dbo.POP_Header WHERE POH_Status =3D 1 GROUP
BY POH_Status

Column 'bv-cluster-sql.contracts.dbo.pop_header.POH_CONTRACT' is
invalid in the select list because it is not contained in either an
aggregate function or the GROUP BY clause.

So, fixing the query ...

SELECT POH_Contract, COUNT(POH_Contract) FROM
[BV-CLUSTER-SQL].Contracts.dbo.POP_Header WHERE POH_Status =3D 1 GROUP
BY POH_Status, POH_Contract

now works.

So, your query may need to be

SELECT `reference`, COUNT(`reference`) AS currently_in_rss FROM
`ministry_profiles` WHERE `rss_feed_include` =3D 1 GROUP BY
`rss_feed_include`, `reference`



Normally COUNT() will count NULLs, but as you are grouping by the
counted column, nulls would be in their own row.


Richard.

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On 15/12/10 21:42, Richard Quadling wrote:
> On 14 December 2010 21:53, Ron Piggott<ron.piggott [at] actsministries.org> wrote:
>>
>> What change is needed to this query so if “currently_in_rss” is NULL it will be assigned a value of 0
>>
>> SELECT `reference`, COUNT(`reference`) AS currently_in_rss FROM `ministry_profiles` WHERE `rss_feed_include` = 1 GROUP BY `rss_feed_include`
>>
>> Ron
>
> Doesn't that query give you an error saying that `reference` isn't in
> the GROUP BY clause?

Nah mysql lets you do it. Other db's enforce it as you pointed out.

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