I have a function like this:
function get_articles($cat=1,$numberposts=1);

it can be used:
get_articles(cat=4&numberposts=6);
//will display 6 posts from category 6

then I want to use that function within another function, like this:

function display_cat($new_cat=1,$new_num=1,$othercontent="")
{
get_articles(cat=$new_cat&numberposts=$new_num)

.......
}


Can I pass function like this ?

> I have a function like this:
> function get_articles($cat=1,$numberposts=1);
>
> it can be used:
> get_articles(cat=4&numberposts=6);
> //will display 6 posts from category 6


You mean

get_articles(cat=4, numberposts=6);

yes?



> then I want to use that function within another function, like this:
>
> function display_cat($new_cat=1,$new_num=1,$othercontent="")
> {
> get_articles(cat=$new_cat&numberposts=$new_num)
>
> ......
> }
>
>
> Can I pass function like this ?

I think you mean

get_articles($new_cat, $new_num);

And you're not passing a function, you're passing variables. You can't
pass functions in PHP. You could pass objects, but you don't need to
here.

> I think you mean
>
> get_articles($new_cat, $new_num);
>
> And you're not passing a function, you're passing variables. You can't
> pass functions in PHP. You could pass objects, but you don't need to
> here.

Thank you very much for your reply.

here is exactly my code:

$article = get_articles(cat=4&numberposts=6);
// then I will extract data from $article

However, I want to pass 2 parametes cat and numberposts from another
function, so I must write another function:

function display_cat($new_cat=1,$new_num=1,$othercontent="")
{
$article=get_articles(cat=$new_cat&numberposts=$new_num)
......
}

My purpose is want to pass $new_cat and $new_num from function
display_cat().
Is is possible ?

Please help me, thank you very much !

BabyBlue wrote:
> I have a function like this:
> function get_articles($cat=1,$numberposts=1);
>
> it can be used:
> get_articles(cat=4&numberposts=6);
> //will display 6 posts from category 6

Wrong group?
This is not PHP; the syntax is wrong.
For the correct PHP syntax read the manual:
http://www.php.net/manual/en/functions.arguments.php

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If you *really* need to mail me, use the address in the Reply-To
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..oO(BabyBlue)

>here is exactly my code:
>
>$article = get_articles(cat=4&numberposts=6);

Should be

$article = get_articles(4, 6);

>However, I want to pass 2 parametes cat and numberposts from another
>function, so I must write another function:
>
> function display_cat($new_cat=1,$new_num=1,$othercontent="")
> {
> $article=get_articles(cat=$new_cat&numberposts=$new_num)

Should be

$article = get_articles($new_cat, $new_num);

> }

Micha

BabyBlue wrote:
> I have a function like this:
> function get_articles($cat=1,$numberposts=1);
>
> it can be used:
> get_articles(cat=4&numberposts=6);
> //will display 6 posts from category 6
>
> then I want to use that function within another function, like this:
>
> function display_cat($new_cat=1,$new_num=1,$othercontent="")
> {
> get_articles(cat=$new_cat&numberposts=$new_num)
>
> ......
> }
>
>
> Can I pass function like this ?
>

No, you are incorrect. You would call it with:

get_articles(4, 6);

"cat=4&numberposts=6" is strictly an HTML implementation. It's not used
within functions like this.

So in your display_cat function, you would call it with

get_articles($new_cat, $numberposts);

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